Given the vector field F=0.4(y-2x)ax-[200/(x2+y2+z2)]az; (a) evaluate |F| at P(-4,3,5); (b) find a unit vector specifying the direction of F at P. Describe the locus of all points for which: (c) Fx=1; (d) |Fz|=2.
Solutions:
(a) evaluate |F| at P(-4,3,5):
Substitute coordinates of point P to the given equation.
F = (0.4y-0.7x)ax-[200/(x2+y2+z2)]az
F = [0.4(3)-0.8(-4)]ax-[-200/(42+32+52)]az
F = (1.2+3.2)ax-(200/50)az
F = 4.4ax-4az
|F| = √[(4.42)+42] = 5.95
(b) find a unit vector specifying the direction of F at P:
aF = F/|F| = (4.4ax-4az)/5.95
aF = 0.740ax-0.673az
(c) Describe the locus of all points for which Fx = 1:
F = Fxax-Fzaz
Fx = 0.4(y-2x)
1 = 0.4y-0.8x
0.4y = 0.8x+1
y = (0.8x+1)/0.4
y = 2x+2.5 (equation of a plane)
(d) Describe the locus of all points for which |Fz| = 2:
|Fz| = √Fz2 = Fz
2 = 200/(x2+y2+z2)
(x2+y2+z2) = 200/2
(x2+y2+z2) = 100 (equation of a sphere)
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